Integrand size = 29, antiderivative size = 99 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {\left (4 b+3 a c^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}{8 x^2}+\frac {1}{8} c^2 \left (4 b+3 a c^2\right ) \arctan \left (\sqrt {-1+c x} \sqrt {1+c x}\right ) \]
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Time = 0.05 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {465, 105, 12, 94, 211} \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\frac {1}{8} c^2 \left (3 a c^2+4 b\right ) \arctan \left (\sqrt {c x-1} \sqrt {c x+1}\right )+\frac {\sqrt {c x-1} \sqrt {c x+1} \left (3 a c^2+4 b\right )}{8 x^2}+\frac {a \sqrt {c x-1} \sqrt {c x+1}}{4 x^4} \]
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Rule 12
Rule 94
Rule 105
Rule 211
Rule 465
Rubi steps \begin{align*} \text {integral}& = \frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {1}{4} \left (4 b+3 a c^2\right ) \int \frac {1}{x^3 \sqrt {-1+c x} \sqrt {1+c x}} \, dx \\ & = \frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {\left (4 b+3 a c^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}{8 x^2}+\frac {1}{8} \left (4 b+3 a c^2\right ) \int \frac {c^2}{x \sqrt {-1+c x} \sqrt {1+c x}} \, dx \\ & = \frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {\left (4 b+3 a c^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}{8 x^2}+\frac {1}{8} \left (c^2 \left (4 b+3 a c^2\right )\right ) \int \frac {1}{x \sqrt {-1+c x} \sqrt {1+c x}} \, dx \\ & = \frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {\left (4 b+3 a c^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}{8 x^2}+\frac {1}{8} \left (c^3 \left (4 b+3 a c^2\right )\right ) \text {Subst}\left (\int \frac {1}{c+c x^2} \, dx,x,\sqrt {-1+c x} \sqrt {1+c x}\right ) \\ & = \frac {a \sqrt {-1+c x} \sqrt {1+c x}}{4 x^4}+\frac {\left (4 b+3 a c^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}{8 x^2}+\frac {1}{8} c^2 \left (4 b+3 a c^2\right ) \tan ^{-1}\left (\sqrt {-1+c x} \sqrt {1+c x}\right ) \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.79 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\frac {1}{8} \left (\frac {\sqrt {-1+c x} \sqrt {1+c x} \left (4 b x^2+a \left (2+3 c^2 x^2\right )\right )}{x^4}+\left (8 b c^2+6 a c^4\right ) \arctan \left (\sqrt {\frac {-1+c x}{1+c x}}\right )\right ) \]
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Time = 4.05 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.95
method | result | size |
risch | \(\frac {\sqrt {c x -1}\, \sqrt {c x +1}\, \left (3 a \,c^{2} x^{2}+4 b \,x^{2}+2 a \right )}{8 x^{4}}-\frac {c^{2} \left (3 c^{2} a +4 b \right ) \arctan \left (\frac {1}{\sqrt {c^{2} x^{2}-1}}\right ) \sqrt {\left (c x -1\right ) \left (c x +1\right )}}{8 \sqrt {c x -1}\, \sqrt {c x +1}}\) | \(94\) |
default | \(-\frac {\sqrt {c x -1}\, \sqrt {c x +1}\, \left (3 \arctan \left (\frac {1}{\sqrt {c^{2} x^{2}-1}}\right ) a \,c^{4} x^{4}+4 \arctan \left (\frac {1}{\sqrt {c^{2} x^{2}-1}}\right ) b \,c^{2} x^{4}-3 \sqrt {c^{2} x^{2}-1}\, a \,c^{2} x^{2}-4 \sqrt {c^{2} x^{2}-1}\, b \,x^{2}-2 \sqrt {c^{2} x^{2}-1}\, a \right )}{8 \sqrt {c^{2} x^{2}-1}\, x^{4}}\) | \(125\) |
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Time = 0.27 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.79 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\frac {2 \, {\left (3 \, a c^{4} + 4 \, b c^{2}\right )} x^{4} \arctan \left (-c x + \sqrt {c x + 1} \sqrt {c x - 1}\right ) + {\left ({\left (3 \, a c^{2} + 4 \, b\right )} x^{2} + 2 \, a\right )} \sqrt {c x + 1} \sqrt {c x - 1}}{8 \, x^{4}} \]
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Timed out. \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\text {Timed out} \]
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Time = 0.37 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.86 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=-\frac {3}{8} \, a c^{4} \arcsin \left (\frac {1}{c {\left | x \right |}}\right ) - \frac {1}{2} \, b c^{2} \arcsin \left (\frac {1}{c {\left | x \right |}}\right ) + \frac {3 \, \sqrt {c^{2} x^{2} - 1} a c^{2}}{8 \, x^{2}} + \frac {\sqrt {c^{2} x^{2} - 1} b}{2 \, x^{2}} + \frac {\sqrt {c^{2} x^{2} - 1} a}{4 \, x^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 268 vs. \(2 (81) = 162\).
Time = 0.29 (sec) , antiderivative size = 268, normalized size of antiderivative = 2.71 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=-\frac {{\left (3 \, a c^{5} + 4 \, b c^{3}\right )} \arctan \left (\frac {1}{2} \, {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{2}\right ) + \frac {2 \, {\left (3 \, a c^{5} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{14} + 4 \, b c^{3} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{14} + 44 \, a c^{5} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{10} + 16 \, b c^{3} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{10} - 176 \, a c^{5} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{6} - 64 \, b c^{3} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{6} - 192 \, a c^{5} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{2} - 256 \, b c^{3} {\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{2}\right )}}{{\left ({\left (\sqrt {c x + 1} - \sqrt {c x - 1}\right )}^{4} + 4\right )}^{4}}}{4 \, c} \]
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Time = 31.05 (sec) , antiderivative size = 650, normalized size of antiderivative = 6.57 \[ \int \frac {a+b x^2}{x^5 \sqrt {-1+c x} \sqrt {1+c x}} \, dx=\frac {\frac {b\,c^2\,1{}\mathrm {i}}{32}+\frac {b\,c^2\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2\,1{}\mathrm {i}}{16\,{\left (\sqrt {c\,x+1}-1\right )}^2}-\frac {b\,c^2\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^4\,15{}\mathrm {i}}{32\,{\left (\sqrt {c\,x+1}-1\right )}^4}}{\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2}{{\left (\sqrt {c\,x+1}-1\right )}^2}+\frac {2\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^4}{{\left (\sqrt {c\,x+1}-1\right )}^4}+\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^6}{{\left (\sqrt {c\,x+1}-1\right )}^6}}-\frac {\frac {a\,c^4\,1{}\mathrm {i}}{1024}-\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2\,3{}\mathrm {i}}{128\,{\left (\sqrt {c\,x+1}-1\right )}^2}-\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^4\,53{}\mathrm {i}}{512\,{\left (\sqrt {c\,x+1}-1\right )}^4}+\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^6\,87{}\mathrm {i}}{256\,{\left (\sqrt {c\,x+1}-1\right )}^6}+\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^8\,657{}\mathrm {i}}{1024\,{\left (\sqrt {c\,x+1}-1\right )}^8}+\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^{10}\,121{}\mathrm {i}}{256\,{\left (\sqrt {c\,x+1}-1\right )}^{10}}}{\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^4}{{\left (\sqrt {c\,x+1}-1\right )}^4}+\frac {4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^6}{{\left (\sqrt {c\,x+1}-1\right )}^6}+\frac {6\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^8}{{\left (\sqrt {c\,x+1}-1\right )}^8}+\frac {4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^{10}}{{\left (\sqrt {c\,x+1}-1\right )}^{10}}+\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^{12}}{{\left (\sqrt {c\,x+1}-1\right )}^{12}}}-\frac {a\,c^4\,\ln \left (\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2}{{\left (\sqrt {c\,x+1}-1\right )}^2}+1\right )\,3{}\mathrm {i}}{8}-\frac {b\,c^2\,\ln \left (\frac {{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2}{{\left (\sqrt {c\,x+1}-1\right )}^2}+1\right )\,1{}\mathrm {i}}{2}+\frac {a\,c^4\,\ln \left (\frac {\sqrt {c\,x-1}-\mathrm {i}}{\sqrt {c\,x+1}-1}\right )\,3{}\mathrm {i}}{8}+\frac {b\,c^2\,\ln \left (\frac {\sqrt {c\,x-1}-\mathrm {i}}{\sqrt {c\,x+1}-1}\right )\,1{}\mathrm {i}}{2}+\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2\,7{}\mathrm {i}}{256\,{\left (\sqrt {c\,x+1}-1\right )}^2}-\frac {a\,c^4\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^4\,1{}\mathrm {i}}{1024\,{\left (\sqrt {c\,x+1}-1\right )}^4}+\frac {b\,c^2\,{\left (\sqrt {c\,x-1}-\mathrm {i}\right )}^2\,1{}\mathrm {i}}{32\,{\left (\sqrt {c\,x+1}-1\right )}^2} \]
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